x^2-(x-4)(x+3)=17

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Solution for x^2-(x-4)(x+3)=17 equation:


Simplifying
x2 + -1(x + -4)(x + 3) = 17

Reorder the terms:
x2 + -1(-4 + x)(x + 3) = 17

Reorder the terms:
x2 + -1(-4 + x)(3 + x) = 17

Multiply (-4 + x) * (3 + x)
x2 + -1(-4(3 + x) + x(3 + x)) = 17
x2 + -1((3 * -4 + x * -4) + x(3 + x)) = 17
x2 + -1((-12 + -4x) + x(3 + x)) = 17
x2 + -1(-12 + -4x + (3 * x + x * x)) = 17
x2 + -1(-12 + -4x + (3x + x2)) = 17

Combine like terms: -4x + 3x = -1x
x2 + -1(-12 + -1x + x2) = 17
x2 + (-12 * -1 + -1x * -1 + x2 * -1) = 17
x2 + (12 + 1x + -1x2) = 17

Reorder the terms:
12 + 1x + x2 + -1x2 = 17

Combine like terms: x2 + -1x2 = 0
12 + 1x + 0 = 17
12 + 1x = 17

Solving
12 + 1x = 17

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 1x = 17 + -12

Combine like terms: 12 + -12 = 0
0 + 1x = 17 + -12
1x = 17 + -12

Combine like terms: 17 + -12 = 5
1x = 5

Divide each side by '1'.
x = 5

Simplifying
x = 5

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